Design Review
elongation
one formula and parameters:
1, the average tensile force prestressed formula and parameters:
where:
Pp-tendon average tensile force (N)
P-side tensioning the tendons tensile force (N)
X-Tension end-to-calculated from the cross-section of the channel Length (m)
θ-calculated from the tension end-to-channel cross-section part of the curve and the tangent of the angle (rad)
k-channel deviation per meter of local influence on the friction coefficient of Sassafras, taking 0.002
μ-prestressed tendons and the pore wall coefficient of friction Sassafras, taking 0.14
2,
nike air force ones, tendon elongation value of the theoretical formula and parameters:
where:
Pp-tendon average tensile force (N)
L-tendon length (mm)
Ap-sectional area of tendons (mm2), take 140 mm2
Ep-tendon elastic modulus (N / mm2), taking 1.95 × 105 N / mm2
Second, the elongation calculation:
1, N1 beam at one end of the elongation:
single strand tensioning tensile force
P = 0.75 × 1860 × 140 = 195300N
X = 15.812 / 2 = 7.906m
θ = 11.4 × π/180 = 0.19897rad
kx + μθ = 0.002 × 7.906 +0.14 × 0.19897 = 0.0436678
Pp = 195300 × (1-e-0.0436678) / 0.0436678 = 191097N
ΔL = PpL / (Ap Ep) = 191097 × 7.906 / (140 × 1.95 × 105) = 55.3mm
compared with the design (55.3-57.1) / 57.1 =- 3.15%
2, N2 beam at one end of the elongation:
single strand tensioning tensile force
P = 0.75 × 1860 × 140 = 195300N
X = 15.821 / 2 = 7.9105m
θ = 12.8 × π/180 = 0.2234rad
kx + μθ = 0.002 × 7.9105 +0.14 × 0.2234 = 0.047097
Pp = 195300 × (1-e-0.047097) / 0.047097 = 190772N
ΔL = PpL / (Ap Ep) = 190772 × 7.9105 / (140 × 1.95 × 105) = 55.27mm
compared with the design (55.27-57.1) / 57.1 =- 3.2%
Tension
a theoretical calculation of elongation, calculated parameters:
1, K-channel per meter local deviation of coefficient of friction Sassafras: Take 0.002
2, μ-tendon Sassafras and the pore wall friction coefficient: Take 0.14
3, Ap-sectional area measured tendons: 140 mm2
4, Ep-tendon elastic modulus measured: 2.02 × 105 N / mm2
5, the anchor under the control of stress: σk = 0.75Ryb = 0.75 × 1860 = 1395 N / mm2
6, the anchor port Friction Loss: 3.3% σk
7, single strand tension side of the sheets Pull control: P = 103.3% × σkAp = 201745N
8, jack length: 56cm
9, the work of anchor length: 7cm
10, length limit board: 2.5cm
11, Tools Anchor length: do not count
II Elongation Tension theory calculation:
1, N1 beam at one end of the elongation:
X = 15.812 / 2 = 7.906m
L = 7.906 + (0.56 +0.07 +0.025) = 8.561m
θ = 11.4 × π/180 = 0.19897rad
kx + μθ = 0.002 × 7.906 +0.14 × 0.19897 = 0.0436678
Pp = 201745 × (1 - e-0.0436678) / 0.0436678 = 197404N
ΔL = PpL / (Ap Ep) = 197404 × 8.561 / (140 × 2.02 × 105) = 59.8mm
2, N2 beam at one end of the elongation:
X = 15.821 / 2 = 7.9105m
L = 7.9105 + ( 0.56 +0.07 +0.025) = 8.566m
θ = 12.8 × π/180 = 0.2234rad
kx + μθ = 0.002 × 7.9105 +0.14 × 0.2234 = 0.047097
Pp = 201745 (1-e-0.047097 ) / 0.047097 = 197068N
ΔL = PpL / (Ap Ep) = 197068 × 8.566 / (140 × 2.02 × 105) = 59.7mm
Third,
nike air force one, oil jack Tension meter readings and the corresponding calculated
one strand tension control stress:
12 steel strand bundle: σcon = 103.3σk = 103.3% × 2343 = 2420.32KN
Second,
air force 1, tension jack No. 1523, 0050, Yau table:
jack regression equation:
P =- 0.35 +0.01035 F
where: P - oil pressure gauge reading (MPa)
F - Jack pull (KN)
(1),
air force ones, 10% σcon = 242.032 KN Time:
P =- 0.35 +0.01035 F =- 0.35 +0.01035 × 242.032 = 2.16MPa
(2), 40% σcon = 968.13KN Time:
P =- 0.35 +0.01035 F =- 0.35 +0.01035 × 968.13 = 9.67 MPa
(3), 70% σcon = 1694.22KN Time:
P =- 0.35 +0.01035 F =- 0.35 +0.01035 × 1694.22 = 17.19 MPa
(4), 100% σcon = 2420.32KN Time :
P =- 0.35 +0.01035 F =- 0.35 +0.01035 × 2420.32 = 24.7 MPa
Third, the tension jack No. 1524, 0054, Yau table:
jack regression equation:
P = 0.21 +0.01022 F:
where: P - oil pressure gauge reading (MPa)
F - Jack pull (KN)
(1), 10% σcon = 242.032KN Time:
P = 0.21 +0.01022 F = 0.21 +0.01022 × 242.032 = 2.68 MPa
(2), 40% σcon = 968.13KN Time:
P = 0.21 +0.01022 F = 0.21 +0.01022 × 968.13 = 10.10 MPa
(3 ), 70% σcon = 1694.22KN Time:
P = 0.21 +0.01022 F = 0.21 +0.01022 × 1694.22 = 17.52 MPa
(4), 100% σcon = 2420.32KN Time:
P = 0.21 + 0.01022 F = 0.21 +0.01022 × 2420.32 = 24.95 MPa
IV, No. 1525 Jack Zhang Pull, 0077, Yau table:
jack regression equation: P =- 0.47 +0.01024 F:
where: P - oil pressure gauge reading (MPa)
F - Jack pull (KN)
(1), 10% σcon = 242.032KN Time:
P =- 0.47 +0.01024 F =- 0.47 +0.01024 × 242.032 = 2.0 MPa
(2), 40% σcon = 968.13KN time
P =- 0.47 +0.01024 F =- 0.47 +0.01024 × 968.13 = 9.44 MPa
(3), 70% σcon = 1694.22KN Time :
P =- 0.47 +0.01024 F =- 0.47 +0.01024 × 1694.22 = 16.88 MPa
(4), 100% σcon = 2420.32KN Time:
P =- 0.47 +0.01024 F =- 0.47 + 0.01024 × 2420.32 = 24.31 MPa
V. 1526 jack tension, 0064, Yau table:
jack regression equation: P =- 0.05 +0.01021 F:
where: P - oil pressure gauge reading (MPa)
F - Jack pull (KN)
(1), 10% σcon = 242.032KN Time:
P =- 0.05 +0.01021 F =- 0.05 +0.01021 × 242.032 = 2.42 MPa
(2) ,
air force one 25th, 40% σcon = 968.13KN when
P =- 0.05 +0.01021 F =- 0.05 +0.01021 × 968.13 = 9.83 MPa
(3), 70% σcon = 1694.22KN Time:
P =- 0.05 +0.01021 F =- 0.05 +0.01021 × 1694.22 = 17.24 MPa
(4), 100% σcon = 2420.32KN Time:
P =- 0.05 +0.01021 F =- 0.05 +0.01021 × 2420.32 = 24.66 MPa
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